Math, asked by jinalsethi2008, 3 months ago

__________ should be added to 90a’ – 4a2 + 6a +8 to get zero.​

Answers

Answered by pihu4976
0

Answer:

let the number be x

then,

x+(90a-4a²+6a+8)=0

x+96a-4a²+8=0

x= 4a²-96a-8

hope it helps you!!

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