show 2-3root5 is an irrational
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proof that root 5 is irrational:
assume that root 5 is rational
root 5 = p/q
where p and q are integers and p/q is in lowest terms.
5 = p^2/q^2
5 q^2 = p^2
5 divides p^2
if 5 divides p^2 then since 5 is prime, 5 must divide p
r = p/5
q^2 = 5 r^2
Which means the 5 must divide q, but if 5 divides p and 5 divides q then p/q is not in lowest terms.
we have a contradiction
sqrt 5 does not equal p/q
sqrt 5 is irrational
proof that 2 - 3 root 5 is irrational
assume that
2 - 3 root 5 is rational
2 - 3 root 5 = r (where r is a rational number
root 5 = (2-r)/3
if r is rational then (2-r)/3 is rational
but root 5 is irrational.
2 - 3 root 5 is irr
proof that root 5 is irrational:
assume that root 5 is rational
root 5 = p/q
where p and q are integers and p/q is in lowest terms.
5 = p^2/q^2
5 q^2 = p^2
5 divides p^2
if 5 divides p^2 then since 5 is prime, 5 must divide p
r = p/5
q^2 = 5 r^2
Which means the 5 must divide q, but if 5 divides p and 5 divides q then p/q is not in lowest terms.
we have a contradiction
sqrt 5 does not equal p/q
sqrt 5 is irrational
proof that 2 - 3 root 5 is irrational
assume that
2 - 3 root 5 is rational
2 - 3 root 5 = r (where r is a rational number
root 5 = (2-r)/3
if r is rational then (2-r)/3 is rational
but root 5 is irrational.
2 - 3 root 5 is irr
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