Question

show √2 is irrational.

Answer 1

https://m.meritnation.com/ask-answer/question/prove-that-root-2-is-irrational/real-numbers/2152272

check on this you get your answer,
if this help plz mark as brainliest.......:)

Answer 2

let root 2be in P/q form
$\sqrt{2} = p \div q$
square both the sides.

$2 = p {2} \div q {2}$
$2q ^{2} = p ^{2}$
2 is divisible by P
2 is divisible by P square
P=2a
$p^{2} = 4a ^{2}$
$2p ^{2} = 4a {}^{2}$
$p {}^{2} = 2a {}^{2}$thus 2 is divisible by P
2 is divisible by P square

hence our assumption is wrong
so it is a irrational no.