Math, asked by shravyasharma04, 10 months ago

show 3 is a zero of 2x^3-x^2-13x-6 and find other zeroes

Answers

Answered by neevlakhani11
0

Answer:

Hello,

P(x) = 2x³-x²-13x-6

Given

3 is a zero of polynomial p(x)

So

By factor theorem

(x - 3) is a factor of p (x)

Now

On dividing

We get the answer as

2x²+5x+2

factorization of this polynomial

2x²+4x+x+2

2x(x+2)+1(x+2)

(x+2)(2x+1)

So,

P(x) = (x-3) (2x²+5x+2)

P(x) = (x-3)(x+2)(2x+1)

So ,

The Zeroes of the polynomial are

3, (-2) and (-1)/2

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