show 3 is a zero of 2x^3-x^2-13x-6 and find other zeroes
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Hello,
P(x) = 2x³-x²-13x-6
Given
3 is a zero of polynomial p(x)
So
By factor theorem
(x - 3) is a factor of p (x)
Now
On dividing
We get the answer as
2x²+5x+2
factorization of this polynomial
2x²+4x+x+2
2x(x+2)+1(x+2)
(x+2)(2x+1)
So,
P(x) = (x-3) (2x²+5x+2)
P(x) = (x-3)(x+2)(2x+1)
So ,
The Zeroes of the polynomial are
3, (-2) and (-1)/2
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