Question

Show 4x^4 + 4x^2 +5 has no real zero​

Answer 1

Step-by-step explanation:

x²(4x²+4)+5=0

x±5

x±1 OK friend this is urs answer

Answer 2

Answer:

To Show if it has no roots

We need to apply "Discriminant" and D<0, So,

D = $\sqrt{b^{2}- 4ac } /2a$

a= 4

b= 4

c = 5

D = $\sqrt{16-80} /8$

D = $\sqrt{-64}$/8

There is should be no negative integers under roots, so it has no roots