Show an expression for the phase difference between voltage and current in an a.c. circuit, when pure capacitance is 90°.
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It turns out that there is a 90° phase difference between the current and voltage, with the current reaching its peak 90° (1/4 cycle) before the voltage reaches its peak. Put another way, the current leads the voltage by 90° in a purely capacitive circuit. The AC power supply produces an oscillating voltage.
Explanation:
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