Question

Show: AP is the perpendicular bisector of BC

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Answer 1

∆ABP≅∆ACP (proved)

BP=CP (CPCT)

∠APB = ∠APC =180⁰ (Linear pair)

But ∠APB = APC (Congruent ∆, corresponding ∠)

∠APB + ∠APB =180= 2∠APB=180

∠APC=∠APC=90⁰

AP is the ⊥ bisector of BC

Answer 2

Hope the photo will help.