Math, asked by prachi4788029, 9 months ago

show by division method that (2t^2-t+3) is a factor of (6t^5-t^4+4t^3-5t^2-t-15)​

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Answered by dsk75
4

Answer:

so, (2t^2-t+3) is a factor of (6t^5-t^4+4t^3-5t^2-t-15)

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