show by long division that 2x+3 is factor of p (x)=4x^4+8x^3+5x^2+x-3?
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The remainder is 0
Therefore 2x+3 is factor of p (x)=4x^4+8x^3+5x^2+x-3
Therefore 2x+3 is factor of p (x)=4x^4+8x^3+5x^2+x-3
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Answer:
2x - 1
⇒4x2−8x+3
−4x2∓2x
--------------------------------------
−6x+3
−6x+3
= 0
Step-by-step explanation:
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