Show by using rate law how much rate of the reaction 2no+ o2->no2 will change if the volume
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The below reaction take place in one step, thus rate of reaction is -
2NO(g) +O2(g) =>2NO2 (g).
Rate=K[NO] ^2[O2].
Suppose X moles of NOand you moles of O2 are taken in the vessel of volume V litre,
Then,
r1=KxV2yV
IfIf the volume of vessel is reduced to V/3 then for the same moles of NO2 and O2
r2=KxV/32yV/32=27KxV2yV.
Therefore, r2r1=27
Or r2=27r1
The rate of the reaction becomes 27 times the initial rate. Order of reaction remains unaffected.
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