Show by using the section formula that points (3,-2) (5,2) and (8,8) are collinear
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We know that
(m/n) = (x - x1)/(x2 - x)
(m/n) = (y - y1)/(y2 - y)
Let
A(x1,y1) = (3,-2)
B(x,y) = (5,2)
C(x2,y2) = (8,8)
(m/n) = (x - x1)/(x2 - x)
(m/n) = (5 - 3)/(8 -5)
(m/n) = 2/3
(m/n) = 2/3
(m/n) = (y - y1)/(y2 - y)
(m/n) = (2 + 2)/(8 - 2)
(m/n) = 4/6 = 2/3
Hence we can say that the given points are collinear.
(m/n) = (x - x1)/(x2 - x)
(m/n) = (y - y1)/(y2 - y)
Let
A(x1,y1) = (3,-2)
B(x,y) = (5,2)
C(x2,y2) = (8,8)
(m/n) = (x - x1)/(x2 - x)
(m/n) = (5 - 3)/(8 -5)
(m/n) = 2/3
(m/n) = 2/3
(m/n) = (y - y1)/(y2 - y)
(m/n) = (2 + 2)/(8 - 2)
(m/n) = 4/6 = 2/3
Hence we can say that the given points are collinear.
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