Question

show explanation
The sum of marks obtained by four friends is 546 and their marks are in the ratio
5:6:7:8. Find the sum of the highest marks and the lowest marks.

Answer 1

Answer:

273

Step-by-step explanation:

let a:b:c:d = 5:6:7:8

sum of ratio = 5+6+7+8 = 26

part of a = 5×546/26

a = 105

part of d = 8×546/26

d = 168

sum of a & d = 105+168

= 273

Answer 2

$\huge \mathtt \red{Answer:-}$

Highest Marks = 168 marks

and

Lowest Marks = 105 marks

and their sum will be :-

168 + 105 = 273

(Explaination in attachment ⬆️)

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