show graphically that system of equations 3x+2y=7; 6x+4y=5 has no solution
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Answer:
There is no solution for the system of equations 3 x + 2 y = 7 and 6 x + 4 y = 5.
Step-by-step explanation:
A system of equations has no solution when:
(a₁ / a₂) = (b₁ / b₂) ≠ (c₁ / c₂).
We have the equations:
3 x + 2 y = 7 and 6 x + 4 y = 5
a₁ = 3
a₂ = 6
b₁ = 2
b₂ = 4
c₁ = 7
c₂ = 5.
Applying the condition:
3 / 6 = 2 / 4 ≠ 7 / 5
1 / 2 = 1 / 2 ≠ 7 / 5.
In the graph also, the lines do not intersect each other at any point.
This means that there is no solution to this system of equations.
Therefore, there is no solution for the system of equations 3 x + 2 y = 7 and 6 x + 4 y = 5.
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