Question

show how √3, 3√5,√512 is in ascending oder​

Answer 1

Answer:

$\sqrt{5 = } \sqrt{5 \times 3 \times 3 } = \sqrt{45}$

Since,

$\sqrt{3} < \sqrt{45} < \sqrt{512}$

Therefore,

$\sqrt{3} < 3 \sqrt{5} < \sqrt{512}$

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