Question

show how √ 5 can be presented on the number line??​

Answer 1

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Answer 2

Step-vise-step explanation

Draw number line as shown in the figure.

Let the point O represent 0(zero) and point A represents 2.

Draw perpendicular AX at A on the number line and cut-off arc AB=1unit.

We have OA=2 units and AB=1unit

Using pythagoras theorem, we have,

${ob}^{2} = {oa}^{2} + {ab}^{2} \\ {ob}^{2} = {2}^{2} + {1}^{2} = 5 \\ {ob}^{2} = \sqrt{5}$

Taking O as the centre and OB= root 5 as radius draw an arc cutting real line at C. Clearly, OC=OB= root5

$hence \: c \: represents \: \sqrt{5} on \: the \: number \: line$

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