show how could you join three resistors each of resistance 9ohm so that the equipment resistance of the combination of 6ohm
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Explanation:
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Resistance of each resistor R=9Ω
Two resistor connected across A and B are connected in parallel.
Equivalent resistance across A and B R
AB
=
R+R
R×R
=
2
R
=
2
9
=4.5Ω
This equivalent resistance is connected in series to another resistor R.
So equivalent resistance across A and C R
AC
=R
AB
+R=4.5+9=
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