show how to calculate the :-
1. Moment of Inertia of a Uniform Rod about a Perpendicular Bisector.
2. Moment of Inertia of a Circular Ring about its Axis.
Answers
Answer:
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Observances: Republic Day Celebrations
Date: Tuesday, 26 January, 2021
Celebrations: Parades, distribution of sweets in schools, speeches and cultural dances
Significance: Inception of Constitution of India
Observed by: India
Type of holiday: Public holiday, National day
Answer:
The moment of inertia about the end of the rod can be calculated directly or obtained from the center of mass expression by use of the Parallel axis theorem. I = kg m². If the thickness is not negligible, then the expression for I of a cylinder about its end can be used.
The moment of inertia of a circular ring about an axis perpendicular to its plane passing through its centre is equal to MR2, where M is the mass of the ring and R is the radius of the ring. Hence, I=MR2.