Question

Show how to factor : 3x^2+10x-8

Best method sir

Answer 1

$\small \bf \pink{hey \: mate \: here \: is \: ur \: ans} \\ \\ \small \bf \pink{ \huge \: solution} \\ \\ \small \bf \pink{3 {x}^{2} + 10x - 8= 0} \\ \\ \small \bf \pink{3 {x}^{2} + (12 - 2)x - 8= 0} \\ \\ \small \bf \pink{3 {x}^{2} + 12x - 2x - 8 = 0} \\ \\ \small \bf \pink{3x(x + 4) - 2(x + 4) = 0} \\ \\ \small \bf \pink{(3x - 2)(x + 4) = 0} \\ \\ \small \bf \pink{x = \frac{2}{3} } \\ \\ \small \bf \pink{and} \\ \\ \small \bf \pink{x = - 4 \: \: ans}$

Answer 2

Answer:

Step-by-step explanation:

3x^2  + 10 x -  8     first u find two numbers whose product  -8[3] = -24

                               and sum 10    

                               pairs whose product  -24 are

                                [-24,1] ,[-12,2],[-8,3][-6,4] [-4,6] ,[-3,8],[-2,12] and [-1,24]

select a pair whose sum 10         [-2,12]

now

3x^2  + 10 x -  8 = 3x^2  + 12 x -2x  -  8

                           = 3x[x+4 ] -2 [x  + 4]

                             =[x+4] [3x -2]