Show how will you connect 3 resistors of 9 Ω each in a circuit to get equivalent resistance of 6 Ω
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Two 9Ω resistors are in series with one 9Ω in parallel connection to get equivalent resistance as 6Ω
equivalent resistance of resistors in series
9Ω + 9Ω = 18Ω
equivalent resistance of tree resistors
1/18 + 1/9 = 3/18
= 1/6
= 6Ω
equivalent resistance of resistors in series
9Ω + 9Ω = 18Ω
equivalent resistance of tree resistors
1/18 + 1/9 = 3/18
= 1/6
= 6Ω
SumaraMorgan:
hope it helpsss.....
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