Question

show how would u connect 3 resistor of 6 ohm so that we get 9 ohm and 4ohm the with diagram ​

Answer 1

Answer:

: To obtain a combined resistance of 9 ohms, three resistors each of resistance 6 ohm should be connected in a parallel circuit and one in series. In a parallel circuit, the equivalent resistance of all the resistors connected is equal to the reciprocal value of the sum of the individual resistances.

Answer 2

$\huge {\underline{\green{Given:-}}}$

• Resistance of Each Resistor = 6

• Number of Resistor = 3

$\huge {\underline{\pink{To Find:-}}}$

• How would we connect to these resistor to get equivalent resistance 4Ω.

$\huge {\underline{\red{Solution:-}}}$

Firstly we calculate the two resistors in Parallel

Equivalent resistance for 2 resistor which are connected in Parallel Connection

• 1/Req = 1/R1 + 1/R2 ......

Substitute the value we get

→ 1/Req = 1/6 + 1/6

→ 1/Req = 2/6

→ 1/Req = 1/3

→ Req = 3 Ω

Now, In this circuit we connect another resistor of 6 ohm . So , we get the equivalent resistance

→ Req = Req + R3

→ Req = 3+6

→ Req = 9Ω

Therefore the two resistor must be connected in parallel and one resistor in series to get 9Ω resistance.

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For 4 Ω

To get 4 Ω equivalent resistance of Resistor we should connect the two resistor in series and one in parallel so, we get the equivalent resistance 4 ohm

Equivalent Resistance in Series = R1 + R2 ..

→ Req (in series) = 6+6

→ Req = 12Ω

Now, One resistor connect in parallel

→ 1/R = 1/6 + 1/12

→ 1/R = 3/12

→ 1/R = 1/4

→ R = 4Ω

So we should follow the given statement to get the 4Ω equivalent resistance.

For more information refer to attachment !!