show how would you connect the three resistors eachof resistence 6 ohm,so that the combination has a resistence of 1. 9 0hm 2. 4 ohm
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See here in 1 case:
Two resistance are connected in parallel and then with series with third one.
We have to find net resistance across A and B.
Let R1 is the equivalent resistance of series connection then 1/R1 = 1/6 +1/6
R1=3 ohm
Now R be equivalent resistance then
R=R1 + 6=3+6=9 ohm
Two resistance are connected in parallel and then with series with third one.
We have to find net resistance across A and B.
Let R1 is the equivalent resistance of series connection then 1/R1 = 1/6 +1/6
R1=3 ohm
Now R be equivalent resistance then
R=R1 + 6=3+6=9 ohm
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yash510:
i am not understand
hey I can explain it
plz tell me
see in first case two resistance are connected in parallel and then connect in series with third one. since each resistance have value 6 ohm. by applying parallel combination and series combination to find net resistance
thnx bro
i clearly understand
I editing the answer and fully solve 1st one. I hope u solved 2 by yourself from figure
ok
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