Question

Show how would you connect three resistors each of resistance 692
so that the combination has a resistance of (i) 9 (2) 4​

Answer 1

Answer:

Explanation:

(i) Two resistors in parallel

Two 6 Ω resistors are connected in parallel. Their equivalent resistance will be

The third 6 Ω resistor is in series with 3 Ω. Hence, the net resistance of the circuit is 6 Ω + 3 Ω = 9 Ω.

(ii) Two resistors in series

Here Rs=6+6=12 Ω let third resistance R3=6 Ω

Two 6 Ω resistors are in series. Their equivalent resistance will be the sum

1/R=1/R1 + 1/R2

=1/12 + 1/6

= 1/12 + 2/12

=3/12

1/R=1/4

R=4

∴ the total resistance is 4 Ω