Show how would you connect three resistors, each of resistance 6ohms, so that the combination has a resistance of (a) 9ohms (b)4ohms.
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(a) Connect to resistors in parallel and then that to the third one in series.
For parallel,
1/R = 1/6+1/6 = 1/3
R = 3 ohm
And now that in series with the third one,
R2 = 6 + R = 6+3 = 9 ohm
(b) Connect two in series and then that altogether in parallel to the third resistor.
R (for series) = 6+6=12 ohm
1/R2 (for total in parallel with 3rd) = 1/R +1/6 = 1/12 + 1/6 = 1/4
R2 = 4 ohm
P.S. my best attempt at drawing
For parallel,
1/R = 1/6+1/6 = 1/3
R = 3 ohm
And now that in series with the third one,
R2 = 6 + R = 6+3 = 9 ohm
(b) Connect two in series and then that altogether in parallel to the third resistor.
R (for series) = 6+6=12 ohm
1/R2 (for total in parallel with 3rd) = 1/R +1/6 = 1/12 + 1/6 = 1/4
R2 = 4 ohm
P.S. my best attempt at drawing
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