Question

Show how would you connect three resistors each of resistance 6 ohm so that the combination of resistance have 4 ohm

Answer 1

Answer:

two resistor of 6 ohm in series and one in parallel so 12 ohm and 6 ohm in parallel will give you an equivalent resistance of 4 ohm

Explanation:

Answer 2

Answer:

Explanation

(i) Two 6 ohm resistors are connected in parallel. Their equivalent resistance will be

$\frac{1}{R_{s} }$ = $\frac{1}{6}$ +  $\frac{1}{6}$ = $\frac{2}{6}$

               = $\frac{1}{3}$

$R_{s}$ = 3 ohm

The third 6 ohm resistor is in series with 3 ohm. Hence,, the net resistance of the circuit is 6 ohm + 3 ohm = 9 ohm

so, the two resistance in parallel

(ii) Here, $R_{s}$ = 6+6 = 12 and let the third resistance be $R_{3}$ = 6 ohm

Two 6 ohm resistors are in series . Their equivalent resistors will be the sum

$\frac{1}{R} =\frac{1}{R_{S} } + \frac{1}{R_{3} }$

$\frac{1}{R} =\frac{1}{12} + \frac{1}{6}$

$\frac{1}{R} = \frac{3}{12}$

$\frac{I}{R} =\frac{1}{4}$

R = 4 ohm

The total resistance is 4 ohm.

So. the two resistors is in series.

Hope this helps!!!!