Show how would you connect three resistors of resistances 6 ohm each, so
that the combination has a resistance of (i) 9 ohm (ii) 4 ohm
Answers
Answer:
(1) 2 parallel and one in series of them two
(2) 2 in series and one is parallel of them two
Explanation:
because in series resistance will add
R = R1 +R2
in parallel combination=. 1/R = 1/R1 + 1/R2
Answer:
answer is given below :
Explanation:
to get a resistance of 9 ohm , connect two 6 ohm resistors in parallel and the resultant parallel resistance in series with the third 6 ohm resistor as given below .
1/6+1/6 = 2/6 or 1/3 . so , Rp = 3.
3 ohm + 6 ohm = 9 ohms
2nd part . to get a resistance of 4 ohms , connect two of the 6 ohm resistor in series with each other . Then , connect the resistance obtained by connecting two six ohm resistor in series with the third 6 ohm resistor in parallel as given below.
6 ohm + 6 ohm = 12 ohm ( series )
1/12 + 1/6 = 3/12 or 1/4 . Rp = 4 ohms .
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