Question

Show how would you join 3 resistors , each of resistance 6 ohm so that the equivalent resistance of the combination is (i) 9 ohm(ii)6 ohm

**REALLY URGENT!!**

Answer 1

Answer:

We can get the values as 18Ω, 2Ω, 9Ω and 4Ω

Here's how:

Use all 3 in series connection

So, R = 6 + 6 + 6

∴ R = 18Ω

Use all 3 in parallel

So, 1/R = 1/6 + 1/6 + 1/6

            = 3/6

⇒ R = 6/3

∴ R = 2Ω

Use 2 in parallel and one in series connection

So, 1/R₁= 1/6 + 1/6

          = 2/6

∴ R₁ = 6/2

       = 3Ω

R₂= 6Ω

Now, R = 3 + 6

∴ R = 9Ω

Use 2 in series and one parallel to it

So, R₁= 6 + 6

         = 12Ω

R₂ = 6Ω

Now connect them in parallel connection,

⇒ 1/R = 1/12 + 1/6

         = 1/12 + 2/12

⇒1/R = 3/12

⇒R = 12/3

∴ R = 4Ω