show how would you join three resistors each of resistance 9 ohm so that the equivalent resistance of the combination is 13.5 ohm 6 Ohm
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Answered by
52
two in parallel and 1 in series for 13.5
Connect 2 resistors in series and one in parallel for 6
when u connect it in series R1+R2 = 18
connect this one parallel to the third one
so 1/Rp= 1/18 + 1/9 = 1+2/18
=3/18
Rp=18/3=6
pls mark it as the brainliest
Connect 2 resistors in series and one in parallel for 6
when u connect it in series R1+R2 = 18
connect this one parallel to the third one
so 1/Rp= 1/18 + 1/9 = 1+2/18
=3/18
Rp=18/3=6
pls mark it as the brainliest
serdan2114:
Thanks
Answered by
20
(1) I KNOW ABOUT THE FIRST ONE ONLY
IF YOU WANT TO GET A EQUIVALENT COMBINATION OF 13.5 OHM
THEN YOU SHOULD CONNECT 1 RESISTOR IN SERIES AND OTHER TWO RESISTORS IN PARALLEL
1/Rp=1/R1+1/R2
1/Rp= 1/9+1/9
1/Rp=2/9
Rp=4.5ohm
when we add Rs and Rp we get=9+4.5=13.5 ohm
IF YOU WANT TO GET A EQUIVALENT COMBINATION OF 13.5 OHM
THEN YOU SHOULD CONNECT 1 RESISTOR IN SERIES AND OTHER TWO RESISTORS IN PARALLEL
1/Rp=1/R1+1/R2
1/Rp= 1/9+1/9
1/Rp=2/9
Rp=4.5ohm
when we add Rs and Rp we get=9+4.5=13.5 ohm
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