Question

Show how would you join three resistors, each of resistance 9  so that the

equivalent resistance of the combination is (i) 13.5  (ii) 6  ?​

Answer 1

Explanation:

It is given 3 resistors, each of which resistance 6Ω.

The equivalent resistance of resistors in series is more than the individual resistance of each resistor. In comparison, the equivalent resistance of resistance in parallel is less than the individual resistance of each resistor.

To get an equivalent resistance of 9Ω, at least one six ohm resistors should be connected in series with the other resistors.

Since,

Req = R1 + R2

9 = 6 + R2

R2 = 3Ω

⟹ R2 < 6Ω

By connecting the remaining two resistors in parallel will yield an equivalent resistance of 3Ω.

(ii) To get an equivalent resistance of 9Ω, no six-ohm resistor should be connected in series with the other resistors.

Let one of the branches have only one 6Ω resistor.

Since, 1/Req = 1/ R1 + 1/R2

1/9 = 1/6 + 1/R2

R2 =12Ω

By connecting the remaining two resistors in series will yield an equivalent resistance of 12Ω.

Hope it will help you✓✓✓

Mark me as Brainliest✓™✓™