show how would you join three resistors‚eachof resistance 9 oms so that the equivalent resistance of the combination is (i)13.5Oms (ii)6Oms?
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(i) first we connect 2 resistors in parallel 1/9+1/9=2/9, then R=9/2,then connect them in series 9/2+9=27/2=13.5 ohms
(ii) for second we will connect 1st two in series which gives- 9+9=18
then connect the result in parallel 1/18+1/9=3/18=1/6=6ohms
(ii) for second we will connect 1st two in series which gives- 9+9=18
then connect the result in parallel 1/18+1/9=3/18=1/6=6ohms
ZaidKhan144:
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