Question

show how you would connect three resistor,each of resistance of 6 ohm,so that the combination has a resistance of 2 ohm​

Answer 1

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☆ We will connect the three resistors of 6 ohm each in parallel so that the combination would has resistance of 2 ohm.

Because we know that in prallel combination,

☆ 1/Total resistance

= 1/R1+1/R2+1/R3......

=》 1/Req

= (1/6+1/6+1/6)ohm.

=》 1/Req = 3/6 ohm.

=》 1/Req = 1/2 ohm.

${\large{\boxed{\blue{=》\:\: Req \:= \:2 \:\:ohm}}}}$

Therefore the combination resistance is equal to 2 ohm.

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