Question

show how you would connect three resistors, each of resistance 6 ohm.so that the combination has a resistance of 9 ohm and 4 Ohm​.

Answer 1

Answer:

Given:

3 resistors of 6 ohm has been provided.

To find:

Combinations of the resistors such that the Equivalent Resistance is

• 9 ohm
• 4 ohm

Diagram:

Please refer to the attached photo to understand better .

Calculation:

For the 1st case:

We shall take two 6 ohm resistors and connect them in parallel. That parallel combination should be connected in series with the 3rd resistor.

For the 2nd case:

Connect two resistors in series. Finally connect this series combination in parallel with the 3rd resistor.

Answer 2

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Given :

3 resistance are , each of resistance is of 6Ω.

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To Find :

(i) Connect them so overall resistance is 9Ω

(ii) We need overall resistance as 4Ω

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Solution :

See attachment for figure

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(i)

For First we have to connect two resistance in parallel and one in series.

⇒ Net Resistance = Put Two in parallel + 1 resistance in series

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Resistance in parallel

⇒(1/6 + 1/6)

⇒(2/6)

⇒(1/3)

⇒3 Ω

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Now add the resistance of series to get net resistance,

⇒Net resistance = 3 + 6

⇒Net resistance = 9 Ω

$\rule{200}{2}$

(ii)

⇒Net resistance = two in series and one in parallel.

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Series resistance = 6 + 6

⇒Series resistance = 12 Ω

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1/Net resistance = 1/12 + 1/6

⇒1/Net resistance = 1 + 2/12

⇒1/Net resistance = 3/12

⇒1/Net resistance = 1/4

⇒Net resistance = 4 Ω

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