Question

show how you would connect three resistors each of resistance 6Ω,so that the combination has resistance of (1)9Ω (2)4Ω.​

Answer 1

Explanation:

(i) see 1st diagram, here two resistors are joined in parallel and one is joined in series with those ones. now R₁ is joined in series with first 6Ω. so, effective resistance, R = 3 + 6 = 9Ω.

(ii) see 2nd diagram, here two resistors are joined in series and these two are joined in parallel with third one.

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