Question

Show how you would connect three resistors, each of R = 6 Ω, so that the combination has a
resistance of 2 Ω and 18 Ω

Answer 1

Answer:

⚪

Connect all three resistance in parallel

1/R = 1/6 +1/6+1/6

R = 2Ω

⚪

By connecting all three resistance in series

R = 6+6+6=18Ω

Answer 2

Answer:

Answer:

⚪

Connect all three resistance in parallel

1/R = 1/6 +1/6+1/6

R = 2Ω

⚪

By connecting all three resistance in series

R = 6+6+6=18Ω