Question

show how you would connect three resistors, each of the resistance 6 ohm, so that the combination has a resistance of (1) 9ohm (2) 4ohm

Answer 1

i)first connect two resistor in parrlell and other one in series in respect to other
But here the values of R1 = R2 = RE = 6 Ohms

So the resutant of two resistors in parallel is (let them be R1 & R2) R1*R2/R1+R2.

Also if same value of resistance are connected in parallel then resultent will be resistance value ÷ no. Of resistors in parallel.

Here the result of two 6 ohms parallel resistors is 3 ohms and this three ohms is connected in series with 6 ohms so the result will 9 ohms.

ii make two resistor in series and one inparllel respect to other

Here Rs=6+6=12 Ω let third resistance R3=6 Ω

Two 6 Ω resistors are in series. Their equivalent resistance will be the sum
∴ the total resistance is 4 Ω  .