Show how you would connect three resistors of 2 Ω, 3 Ω and 6 Ω resistance so that
the combination has a resistance of 1 Ω.
Answers
Answered by
5
Explanation:
We ,know that when we connects resistance in parallel then the resultant resistance will decrease.
So,
R=1/2+1/3+1/6
R=(3+2+1)/6=6/6=1ohm
Answered by
2
Explanation:
when all the resistors are connected in parallel then the combination becomes one ohm
1/2+1/3+1/6
3+2+1/6
6/6
1 ohm
Similar questions