show how you would connect three resistors of 6 ohm so that the combination has a resistor of 4 ohm
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Show how you would connect three resistors, each of resistance 6 Ω, so that the combination has a resistance of (i) 9 Ω, (ii) 4 Ω. The third 6 Ω resistor is in series with 3 Ω. Hence, the net resistance of the circuit is 6 Ω + 3 Ω = 9 Ω. ∴ the total resistance is 4 Ω.
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