Question

show how you would connect threeresistors,each of resistance 6 ohms ,so that the combination has a resistance of 9 ohm

Answer 1

Hey...
I would connect first two resistors in parallel combination and the third one in series combination with the previous one.
Then, total resistance will be 9 ohm.
In parallel, 1/6+1/6 = 3
Then in series, 3+6 = 9.
Hope this would help you .
Mark it as brainliest if you like.
@ Saadya

Answer 2

If all are connected in series
R = 6 + 6 + 6 = 18 Ω

If all are connected parellel
R = 1/6 + 1/6 + 1/6 = 0.5 Ω

If two are connected in parellel and one in series
R = (1/6 + 1/6)^-1 + 6
R = 3 + 6
R = 9 Ω

Hence arrangement should be 2 in parellel and one in series.