show how you would connect tree resistos, each of 6R, so that the combination has a resistance of 9 ohm, 4 ohm.
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The first condition that is 9 ohm ...
1) One 6R resistor in series to 2 6R resistors in parallel which will give 6R + 6R/2 = 9R ohms
2) two resistors in series of 6R ohm each and one resistor of 6R ohm in parallel
》6R + 6R = 12R ---- series
1/Rp = 1/12R + 1/6R = 4R ohms
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