Question

Show if the total surface area of a sphere is same that of the total lateral surface of a right circular cylinder and if that is enclosed.

Answer 1

$\mathfrak{\large {\underline {\underline{Answer \: : - }}}}$

Proved !!

$\mathfrak { \large{\underline {\underline{Explanation \: : - }}}}$

Let the radius of the sphere be r cm.

Then,

Surface area of the sphere = 4πr² cm²　　　　　 　　　　　　 ...(i)

The radius and height of a right circular cylinder that just encloses the sphere of radius r and 2r respectively.

Surface area of the cylinder = 2πr x 2r

= 4πr² cm²　　　　　　　　...(ii)

From (i) and (ii), we have

Surface area of the sphere is equal to the surface area of the cylinder that just encloses the sphere.

Answer 2

hello

circumference of the base = 2πr = 88 cm.

2πr = 88

r = 88*7/2*44

r = 14 cm.

T.s.a = 2π r(r+h)

6512= 2*22/7*14(14+h)

6512= 88(14+h)

6512= 1232+88h

6512-1232=88h

5280 = 88h

h = 5280/88

h = 60 cm

vol. of cylinder = π*r^2*h

= 22/7*(14)^2*60

= 22/7*196*60

= 36960 cm^2