Question

Show<br />K-2<br />that the lines<br />– 3-2 – 2-3 an<br />n-2<br />I<br />4-3 - 2-4<br />42<br />intersect, uso find the coordinates of<br />the point of intersection find the<br />egnction at the plane containing<br />the two lines.​

Answer 1

Step-by-step explanation:

it is atoo difficult do I can't do it

Answer 2

Answer:

Let the line segment A(5, -6) and B(-1, -4) is divided at point P(0, y) by y-axis in ratio m:n

:. x = \frac{mx2+nx1}{m+n

and y = \frac{my2+ny1}{m+n

Here, (x, y) = (0, y); (x1, y1) = (5, -6) and (x2, y2) = (-1, -4)

So , 0 = \frac{m(-1)+n(5)}{m+n}

=> 0 = -m + 5n

=> m= 5n

=> \frac{m}{n}

= \frac{5}{1}

=> m:n = 5:1

Hence, the ratio is 5:1 and the division is internal.Now,

y = \frac{my2+ny1}{m+n}

=> y = \frac{5(-4)+1(-6)}{5+1}

=> y = \frac{-20-6}{6}

=> y = \frac{-26}{6}

=> y = \frac{-13}{3}

Hence, the coordinates of the point of division is (0, -13/3).