Question

show mathematically 1331 earths can be accommodated in the Jupiter...​

Answer 1

Radius of Jupiter is 11 times that off earth .

Let the radius of earth be r units then the radius of Jupiter = 11r units .

Now, Volume of the earth = 4/3πr^3 cubic units .....(1).

Volume of the Jupiter = 4/3π(11r^3 )cubic units .= 4×1331/πr^3 cubic units ........(2).

On comparing (1) and (2),

No of earths that can be accommodated in Jupiter = 1331