Math, asked by pph, 1 year ago

show me how.
$1 \times 0 = 9 \times 0 \\ = 1 = 9 \times 0 \div 0 \\ = 1 = 9$

Answers

Answered by anmol6097

..................HEYA..............
HERE IS YOUR ANSWER

**1×0=9×0
thwn take 0 to right had side and when we take 0 to right hand side tge sign of mutiply will change into divide..
Therefore,1=9×0÷0
then if we divide 0 by 0 it comes 0
therefore 1=9

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pph: no I mean why but 1 is not equal to 9

pph: u can put any number it will be equal to each other

pph: tell me fast

pph: anyone

Answered by Bhavya7520

1=9×0Hey mate here is your answer

• 1×0 = 9×0 because 1×0=0 and 9×0= 0 so, they are equal. The answer is 0=0

• 1=9×0÷0 here 0÷0 is 0
so, 1=9

Hope it helps you
Thank you

Hope it helps you
Thank you

pph: I mean why

pph: 1 is not equal to 9

pph: tell ne

pph: fast

anmol6097: but when we take 1 to the right side it is divided be 9 then answer is 9

pph: then 0= 9

anmol6097: then on the left side it will be 1 cause there is no no. there

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