show me the process
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using law of conservation of momentum
initial momentum=final momentum
initial momentum=0
final momentum=3×4+1×v
0=12+v
v=-12m/s
there fore velocity of lighter mass is 12m/s in opposite direction with respect to heavier mass.
initial momentum=final momentum
initial momentum=0
final momentum=3×4+1×v
0=12+v
v=-12m/s
there fore velocity of lighter mass is 12m/s in opposite direction with respect to heavier mass.
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