Question

show on number line
$\sqrt{5}$

Answer 1

Hope its helps ..............

Answer 2

Heya , here .

Given represent √5 on number line
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We know that ,

$\sqrt{5} = \sqrt{4 + 1} = \sqrt{ {2}^{2} + {1}^{2} }$
Draw right angled triangle OPQ , such that

OQ = 2 units
PQ = 1 unit
and ∆OQP = 90°

NOW , by using Pythagoras theorem , we have

OP² = OQ² + PQ² = 2² + 1²
=> OP = √4+1 = √5

Now, take O as center OP = √5 as radius, Draw an Arc , whice intersects the line at point R.
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Hope it's helps you.
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