Question

show proper steps fir(2n-2)(2n-1)2n/2n!=11×(n-2)(n-1)n/n!​

Answer 1

Answer:

(2n!)

=2

n

(1.3.5...(2n−1))

RHS =(1.3.5...(2n−1))2

n

Multiply and divide by 2.4.6...2n on RHS

[1.3.5...(2n−1)]2

n

=(1.3.5...(2n−1))2

n

×

2.4.6....2n

2.4.6...

=

2.4.6....2n

[1.3.5...(2n−1)]2

=

2.4.6....2n

[(2n)(2n−1)....5.4.3.2.1]2

n

=

2.4.6....2n

(2n)!2

n

=

2

n

(1.2.3..n)

(2n)!2

n

=

n!

(2n)!

= LHS .proved