show show show how would join 3 resistors each of resistance 9ohms so that the equipment resistance of the combination is 13.5ohm?
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Resistance of each resistor R=9Ω
Two resistor connected across A and B are connected in parallel.
Equivalent resistance across A and B RAB=R+RR×R=2R=29=4.5Ω
This equivalent resistance is connected in series to another resistor R.
So equivalent resistance across A and C RAC=RAB+R=4.5+9=13.5Ω
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