Show tha. X+3 is a factor of 69+ 11x-x2 +x3
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Given polynomial
p(x) = x³-x²+11x+69
To check whether (x+3) is a factor of the given polynomial or not
put x+3= 0
x= -3
if p(-3)= 0
Then we can say that (x+3) is a factor of the given polynomial
Now put this value of x in the given polynomial
p(-3)= (-3)³-(-3)²+11(-3)+69
p(-3)= -27-9-33+69
p(-3)= -69+69
p(-3)= 0
Thus (x+3) is a factor of the given polynomial
✌^_^
Swarup1998:
Great thanks.(:
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