Show that 0.0001728 is a perfect cube. Also find the number whose cube is 0.0001728.
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Answered by
3
Answer:
0.00012
Step-by-step explanation:
if 12×12×12=1728
The same thing is here
Just write all the zeroes and then instead of 1728 write 12.
Hope this helpful:)
Answered by
3
ANSWER
cube root of 0.0001728 is 0.00012
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