Question

show that 0.2353535... ... can be enpressed in
form p/q where p and q are integers and q≠0​

Answer 1

Let 0.2353535...be x

x=0.2353535...

100 * x =0.2353535...*100

100x =23.53535...

100x=23.3 + .2353535...(23.3+.23535..=23.53535)

100x=23.3 + x (0.23535..=x)

100x - x =23.3

99x = 23.3

x =23.3/99

x=23.3 * 10/99 * 10

x = 233/990

Therefore correct answer is 233/990

Answer 2

Answer:

Step-by-step explanation:

let s keep x as 0.23535                                            =         1

so 10x=2.3535                                                              =     2

so 100x=23.53535                                                       =       3

so 1000x=235.3535                                                      =      4

now equation 4 - 1

so

1000x=235.3535

-   10x=     2.3535

990x =233.0000    so x=233÷990

                                     which can be written as 233 by 990