Show that 0.3333 = 0.3bar only on 3 can be expressed in the form p/q where p q are integers and q not equal to zero
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Answered by
4
let x = 0.3bar .........equation (i)
10 x = 3.3 .......... equation (ii)
then ,
subtract eq (i) from eq (ii)
10x-x = 3.3-0.3
= 9x = 3
x=3/9
x=1/3
10 x = 3.3 .......... equation (ii)
then ,
subtract eq (i) from eq (ii)
10x-x = 3.3-0.3
= 9x = 3
x=3/9
x=1/3
Answered by
25
Answer:
Given: 0.3 bar.
So, let us assume variable (a) as 0.3 bar.
⇢ a = 0.3333...
⇢ 10a = 10 × (0.333...) = 3.333...
⇢ 3.333... = 3 + a
⇢ a = 0.333...
⇢ 10a = 3 + a
⇢ 9a = 3
⇢ a = 1/3
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